Algebraic Direct and Inverse Proportion
Direct Proportion (Algebraic)

If two variables y and x are in direct proportion, we can write down an equation connecting them.

Equation for direct proportion

  y = kx  where k is a constant.

  
Examples of problems

1) Given that y is directly proportional to x and that y = 56 when x = 8. Calculate y when x = 12.
 

a) Find the value of k: y = kx x = 8 y = 56

56 = k x 8

k = 56/8

k = 7

 
 b) Substitute k = 7 into the equation: y = 7x.

 

 

 

‘when x = 12’
      
y = 7 x 12
 
y = 84


2) Given that p is directly proportional to t2 and that p = 16 when t = 2.
 

a) Calculate p when t = 5.

b) Calculate t when p = 81.
 


a) p = kt2  
     
 
  16 = k x 4
 
 
 
    k = 4
 
 
    p = 4t2
 
(t = 5)
 
 
    p = 4 x 25
 
 
    p = 100
   
b) p = 4t2
 
(p = 81)
                  81 = 4 x t2
 
 
                  t2 = 81/4
 
 
                  t = 9/2

                t = 4,5
 

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Inverse Proportion

If two variables y and x are in inverse proportion, the equation is: y = k/x

Examples of problems

1) If y is inversely proportional to x and y = 5 when x = 4,
  a) Calculate y when x = 10. b) Calculate x when y = 40.

a) y = k/x
 
  5 = k/4
   
  k = 20
     
  y = 20/x
 
x = 10
 
  y = 20/10
 
  y = 2
   
  b) 40 = 20/x
  x = 0,5
   
If f is inversely proportional square_root_symbol w and f = 10 when w = 16,
a) Calculate f when w = 9. b) Calculate w when f = 4.

  a) f = k/square_root_symbolw  
     
  10 = k/square_root_symbol16  
     
  10 = k/4
 
k = 40
 
     
  f = 40/square_root_symbol9
 
w = 9
 
  f = 40/3
 
f = 13,3 (one decimal point) 
     
  b) 4 = 40/square_root_symbolw  
     
  vw = 40/4  
     
  square_root_symbolw =10
 
w = 100
 

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