Rules and Examples
The P (GG) can be written as P (G) and P (G). Use of the word 'and' indicates that we multiply the probabilities.
When the word 'or' can be used, it indicates (+), so we add the probabilities.
Example 1: In a bag of green and blue discs, what is the probability of selecting two discs of different colours, if the first disc is returned before selecting the second.
P(different colours)
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= P(GB) or P(BG)
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= (4/10 x 6/10) + (6/10 x 4/10)
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= 48/100
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= 0,48 |
Example 2: Twins Lerato and Kagiso are taking a driving test. If the probability of Lerato passing is 0,6 and the probability of Kagiso passing is 0,2, what is the probability of only one twin passing?
P (Lerato fails) = 1 – 0,6 = 0,4
P (Kagiso fails) = 1 – 0,2 = 0,8
If only one twin passes then P (Lerato passes and Kagiso fails) = 0,6 x 0,8 = 0,48
OR
P (Lerato fails and Kagiso passes)= 0,4 x 0,2 = 0,08
So P (only one twin passes)
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= 0,48 + 0,08 |
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= 0,56 |
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Mutually Exclusive Events
P (A or B) = P (A) + P (B) can only be used when A and B are mutually exclusive events, i.e. they cannot happen together.
Example 1: Three cards are presented (4 of Clubs, 3 of Diamonds and 5 of Spades). If one is selected, what is the probability of getting a 4 or a Club?
We cannot say P (4 or Club) = P (4) + P (Club) because they can happen together. The 4 can also be a Club, so the events are not mutually exclusive.
Example 2: The probability that the weather will be good on Monday is 0,3.
If it is good, the probability that I can get on my bus is 0,8. If it is not good, the probability that I can get on my bus is 0,2.
Find the probability that I can get on my bus on Monday.
P (weather fine and getting on bus)
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= 0,3 x 0,8
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= 0,24 |
OR |
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P (weather not fine and getting on bus)
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= 0,7 x 0,2
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= 0,14
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P (getting on bus)
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= 0,24 + 0,14
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= 0,38 |
Example 3: When Jane goes shopping, the probability she travels by bus is 0,25, by taxi is 0,1 and on foot is 0,6. What is the probability that she returns (a) by bus or taxi, (b) by bus or on foot?
a) By bus or taxi
b) By bus or on foot
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