Factorising


In algebra, we factorise by putting brackets into the expression.

There are three methods of factorising. 


Method 1

Find a common factor.

Example 1: Factorise 3y + 6.

In this case, 3 is a common factor because it will divide into 3y and 6.

Therefore the answer is written as:

  3(y + 2)

In the next example there are two common factors.

Example 2: Factorise 5y2 – 10y.

5 and y are factors, so the answer is:

  5y (y – 2)

When asked to factorise, we must take out all the common factors.
 

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Method 2

A quadratic expression contains a squared term as its highest power.

Example 1: Factorise y2 + 5y + 6.

In this method we use two brackets. Inside these, we put the factors of the first and last terms as follows:

y2 + 5y + 6
          
 (y y)       (6 1)
(3 2)
Factors of the first term
     
Factors of the last term

Note: There are two pairs of factors of the last term in this case. We choose the pair that adds up to the middle term (in this case, 5).

So the answer is (y +3 )(y + 2).

The signs of the terms can be different, as in the following case.

Example 2: Factorise 

 y2 + 3y – 10.

   
 
 
 

(y, y)       (–5, 2)

                 (5, –2)
                 (–10, 1)
                 (10, –1)

In this case, only 5 + –2 = 3 (which is the middle term).

Answer = (y + 5 )( y – 2)

Example 3: Factorise   x2 – 7x + 12.
 
(x, x)      (– 3, – 4)
– 3 + – 4 = – 7  (which is the middle term)

Answer: (x – 3 )(x – 4)
 

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Method 3

This method is for expressions containing two squared terms and the sign between them must be minus.

Example 1: Factorise x2 – 9.

Both x2 and 9 are squared terms and a minus is between them so we can factorise in this way.

  x2
 – 
9
(x, x)   (3, 3)
      (x + 3)   (x - 3)

Example 2: Factorise   y2 – 25.
  (y, y) (5, 5)
  (y + 5)(y – 5)
Note: There is a + sign is in one bracket and a – sign in the other.
 Combinations of these methods can be used on some expressions.

Example 3: Factorise 2y2 – 8.

Common factor:

 2(y2 – 4)
Difference between two squares:

 2(y + 2)(y – 2)

Note: We can check any answer by removing the brackets. This is called ‘expanding brackets’.

For example, 3(y + 2) = 3 x y + 3 x 2 = 3y + 6.

Note: We multiply everything inside the bracket by 3.

5y(y – 2) = 5y x y + 5y x – 2 = 5y2 – 10y

 
 

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Double Brackets

Example 1
 
(y + 3)(y + 2) = y(y + 2) + 3(y + 2)

= y2 + 2y + 3y + 6

= y2 + 5y + 6

Note: We multiply the second bracket by y and then by 3.

Example 2
 
(y + 5)(y – 2) = y(y – 2) + 5(y – 2)

= y2 – 2y + 5y – 10

= y2 + 3y – 10


Example 3
 
(x – 3)(x – 4) = x(x – 4) – 3(x – 4)

= x2 – 4x – 3x + 12

= x2 – 7x + 12

 
Note: This time we multiply by –3. This changes the signs in the second bracket.

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